48t^2-28t+2=0

Solution for 48t^2-28t+2=0 equation:

Simplifying
48t2 + -28t + 2 = 0

Reorder the terms:
2 + -28t + 48t2 = 0

Solving
2 + -28t + 48t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '2'.
2(1 + -14t + 24t2) = 0

Factor a trinomial.
2((1 + -12t)(1 + -2t)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + -12t)' equal to zero and attempt to solve:

Simplifying
1 + -12t = 0

Solving
1 + -12t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -12t = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -12t = 0 + -1
-12t = 0 + -1

Combine like terms: 0 + -1 = -1
-12t = -1

Divide each side by '-12'.
t = 0.08333333333

Simplifying
t = 0.08333333333
Subproblem 2
Set the factor '(1 + -2t)' equal to zero and attempt to solve:

Simplifying
1 + -2t = 0

Solving
1 + -2t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2t = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2t = 0 + -1
-2t = 0 + -1

Combine like terms: 0 + -1 = -1
-2t = -1

Divide each side by '-2'.
t = 0.5

Simplifying
t = 0.5
Solution
t = {0.08333333333, 0.5}